Critical angle will be maximum, when light travels from

Question

Critical angle will be maximum, when light travels from (A) Glass to air (B) Glass to water (C) Water to air (D) Diamond to air

Tardigrade Admin · Accepted Answer

As sin θc = (1/μ) = (μ2/μ1) (μ1 > μ2 ) μDiamond > μglass > μwater > μair (μ water /μ glass) will be maximum in the given options . So, critical angle will maximum when light travels from glass to water.

Q. Critical angle will be maximum, when light travels from

Glass to air

Glass to water

Water to air

Diamond to air

As $sin θ_{c} = \frac{1}{μ} = \frac{μ _{2}}{μ _{1}} (μ_{1} > μ_{2})$
$μ_{D iam o n d} > μ_{g l a ss} > μ_{w a t er} > μ_{ai r}$
$\frac{μ _{w a t er}}{μ _{g l a ss}}$ will be maximum in the given options .
So, critical angle will maximum when light travels from glass to water.

Q. Critical angle will be maximum, when light travels from

Glass to air

Glass to water

Water to air

Diamond to air

As sinθc​=μ1​=μ1​μ2​​(μ1​>μ2​) μDiamond​>μglass​>μwater​>μair​ μglass​μwater​​ will be maximum in the given options . So, critical angle will maximum when light travels from glass to water.

As $sin θ_{c} = \frac{1}{μ} = \frac{μ _{2}}{μ _{1}} (μ_{1} > μ_{2})$
$μ_{D iam o n d} > μ_{g l a ss} > μ_{w a t er} > μ_{ai r}$
$\frac{μ _{w a t er}}{μ _{g l a ss}}$ will be maximum in the given options .
So, critical angle will maximum when light travels from glass to water.