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Q. Critical angle will be maximum, when light travels from

COMEDKCOMEDK 2009Ray Optics and Optical Instruments

Solution:

As $\sin \theta_{c} = \frac{1}{\mu} = \frac{\mu_{2}}{\mu_{1}} \left(\mu_{1} > \mu_{2} \right) $
$\mu_{Diamond} > \mu_{glass} > \mu_{water} > \mu_{air}$
$ \frac{\mu _{water} }{\mu _{glass}} $ will be maximum in the given options .
So, critical angle will maximum when light travels from glass to water.