Cr2O2-7+X xrightarrow H+ Cr3++H2O + oxidised product of X . X in the above reaction cannot be

Question

Cr2O2-7+X xrightarrow H+ Cr3++H2O + oxidised product of X . X in the above reaction cannot be (A) C2O2-4 (B) SO2-4 (C) S2- (D) Fe2+

Tardigrade Admin · Accepted Answer

Cr2O2-7+ X xrightarrow H+ Cr3++H2O + oxidised product of X In the given reaction X is oxidised and hence acting as reducing agent. Out of given choices SO2-4 cannot act as reducing agent, because sulphur is present in its highest oxidation state, +6

Q. $C r_{2} O_{7}^{2 -} + X H^{+} C r^{3 +} + H_{2} O$ + oxidised product of $X$ . $X$ in the above reaction cannot be

$C_{2} O_{4}^{2 -}$

$S O_{4}^{2 -}$

$S^{2 -}$

$F e^{2 +}$

$C r_{2} O_{7}^{2 -} + X H^{+} C r^{3 +} + H_{2} O$ + oxidised product of $X$ In the given reaction $X$ is oxidised and hence acting as reducing agent. Out of given choices $S O_{4}^{2 -}$ cannot act as reducing agent, because sulphur is present in its highest oxidation state, $+ 6$

Q. Cr2​O72−​+XH+​Cr3++H2​O + oxidised product of X . X in the above reaction cannot be

C2​O42−​

SO42−​

S2−

Fe2+