Question

$C{r}^{2+}$ and $M{n}^{3+}$ both have $d^4$ configuration. Thus

• A. both are reducing agents.
• B. both are oxidizing agents.
• C. $C{r}^{2+}$ is an oxidizing agent while $M{n}^{3+}$ is a reducing agent.
• D. $M{n}^{3+}$ is an oxidizing agent while $C{r}^{2+}$ is a reducing agent.

Answer 1

Answer: (D)

$M{n}^{3+}+e^{-}\to M{n}^{2+}$

Extra stability is gained when $M{n}^{3+}$ is reduced to $M{n}^{2+}$ and is thus an oxidizing agent.
$C{r}^{2+}\to C{r}^{3+}+e^{-}$