Covalent character of the following compounds LiCl, BaCl2, AlCl3, CCl4 is in the order

Question

Covalent character of the following compounds LiCl, BaCl2, AlCl3, CCl4 is in the order (A) LiCl < BaCl2 < CCl4 < AlCl3 (B) CCl4 < AlCl3 < LiCl < BaCl2 (C) BaCl2 < LiCl < AlCl3 < CCl4 (D) AlCl3 < LiCl < BaCl2 < CCl4

Tardigrade Admin · Accepted Answer

Crystal radii beginmatrixLi →1.52 mathringA Ba arrow2.22 mathringA Al arrow1.43 mathringA C →0.77 mathringA endmatrix Carbon is smallest in size. So, it has highest polarising power and so most covalent. So, the order is BaCl2< LiCl < AlCl3< CCl4

Q. Covalent character of the following compounds $L i Cl$ , $B a C l_{2}$ , $A lC l_{3}$ , $CC l_{4}$ is in the order

$L i Cl < B a C l_{2} < CC l_{4} < A lC l_{3}$

$CC l_{4} < A lC l_{3} < L i Cl < B a C l_{2}$

$B a C l_{2} < L i Cl < A lC l_{3} < CC l_{4}$

$A lC l_{3} < L i Cl < B a C l_{2} < CC l_{4}$

Crystal radii $L i \to 1.52 \overset{˚}{A} B a \to 2.22 \overset{˚}{A} A l \to 1.43 \overset{˚}{A} C \to 0.77 \overset{˚}{A}$
Carbon is smallest in size. So, it has highest polarising power and so most covalent. So, the order is $B a C l_{2} < L i Cl < A lC l_{3} < CC l_{4}$

Q. Covalent character of the following compounds LiCl, BaCl2​, AlCl3​, CCl4​ is in the order

LiCl<BaCl2​<CCl4​<AlCl3​

CCl4​<AlCl3​<LiCl<BaCl2​

BaCl2​<LiCl<AlCl3​<CCl4​

AlCl3​<LiCl<BaCl2​<CCl4​