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Tardigrade
Question
Mathematics
cot-1 [(cos α)(1/2)] + tan-1[(cos α)(1/2)] = x then sin x =
Q.
co
t
−
1
[(
cos
α
)
2
1
]
+
t
a
n
−
1
[(
cos
α
)
2
1
]
=
x
then
s
in
x
=
1375
208
Inverse Trigonometric Functions
Report Error
A
1
100%
B
co
t
2
(
α
/2
)
0%
C
t
an
α
0%
D
co
t
(
α
/2
)
0%
Solution:
Using
t
a
n
−
1
θ
+
co
t
−
1
θ
=
2
π
=
x
∴
s
in
x
−
s
in
2
π
−
1