Question

$\cos \left(540^{\circ }-\theta \right)-\sin \left(630^{\circ }-\theta \right)$ is equal to

• A. 0
• B. $2\cos \theta$
• C. $2\sin \theta$
• D. $\sin \theta -\cos \theta$

Answer 1

Answer: (A)

$\cos \left(540^{\circ }-\theta \right)-\sin \left(630^{\circ }-\theta \right)=-\cos \theta +\cos \theta =0$