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Tardigrade
Question
Mathematics
|cos 15°&sin 15° sin 75°&cos 75°|=
Q.
∣
∣
cos
1
5
∘
s
in
7
5
∘
s
in
1
5
∘
cos
7
5
∘
∣
∣
=
1451
198
Determinants
Report Error
A
0
59%
B
5
15%
C
3
21%
D
7
6%
Solution:
We have
∣
∣
cos
1
5
∘
s
in
7
5
∘
s
in
1
5
∘
cos
7
5
∘
∣
∣
=
=
cos
7
5
∘
cos
1
5
∘
−
s
in
7
5
∘
s
in
1
5
∘
=
cos
(
7
5
∘
+
1
5
∘
)
=
cos
9
0
∘
=
0