Correct order of freezing point of 1 M solution of sucrose, KCl, BaCl2 and AlCl3 is

Question

Correct order of freezing point of 1 M solution of sucrose, KCl, BaCl2 and AlCl3 is (A) Sucrose >KCl>BaCl2>AlCl3  (B)  AlCl3>BaCl2>KCl > Sucrose (C) BaCl2>KCl>AlCl3> Sucrose (D)  KCl>BaCl2>AlCl3> Sucrose

Tardigrade Admin · Accepted Answer

Depression in freezing point is a colligative property, it means that as the number of particles (ions) of solute increases, freezing point of the solution decreases.
Sucrose

⟶

not ionised

K Cl ⇌ 2 ions K^{+} + C l^{-}

B a C l_{2} ⇌ 3 ions B a^{2 +} + 2 C l^{-}

A lC l_{3} ⇌ 4 ions A l^{3 +} + 3 C l^{-}

Hence, the correct order of freezing point is
Sucrose

> K Cl > B a C l_{2} > A lC l_{3}

Q. Correct order of freezing point of $1 M$ solution of sucrose, $K Cl, B a C l_{2}$ and $A lC l_{3}$ is

Sucrose $> K Cl > B a C l_{2} > A lC l_{3}$

$A lC l_{3} > B a C l_{2} > K Cl >$ Sucrose

$B a C l_{2} > K Cl > A lC l_{3} >$ Sucrose

$K Cl > B a C l_{2} > A lC l_{3} >$ Sucrose

Q. Correct order of freezing point of 1M solution of sucrose, KCl,BaCl2​ and AlCl3​ is

Sucrose >KCl>BaCl2​>AlCl3​

AlCl3​>BaCl2​>KCl> Sucrose

BaCl2​>KCl>AlCl3​> Sucrose

KCl>BaCl2​>AlCl3​> Sucrose

Q. Correct order of freezing point of $1 M$ solution of sucrose, $K Cl, B a C l_{2}$ and $A lC l_{3}$ is

Sucrose $> K Cl > B a C l_{2} > A lC l_{3}$

$A lC l_{3} > B a C l_{2} > K Cl >$ Sucrose

$B a C l_{2} > K Cl > A lC l_{3} >$ Sucrose

$K Cl > B a C l_{2} > A lC l_{3} >$ Sucrose