Correct order of decreasing thermal stability is as

Question

Correct order of decreasing thermal stability is as (A) NH3 > PH3 > AsH3> SbH3 (B) PH3> NH3> AsH3> SbH3 (C) AsH3> PH3> NH3 > SbH3 (D) SbH3> AsH3> PH3> NH3

Tardigrade Admin · Accepted Answer

The thermal stability of the hydrides of nitrogen family or group

15

elements decreases on moving downwards in the group. Therefore,

N H_{3}

is the most stable and

B i H_{3}

is the least stable. The stability of the hydrides of group

15

elements decreases in the order

N H_{3} > P H_{3} > A S H_{3} > S b H_{3} > B i H_{3}

Q. Correct order of decreasing thermal stability is as

$N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$

$P H_{3} > N H_{3} > A s H_{3} > S b H_{3}$

$A s H_{3} > P H_{3} > N H_{3} > S b H_{3}$

$S b H_{3} > A s H_{3} > P H_{3} > N H_{3}$

Q. Correct order of decreasing thermal stability is as

NH3​>PH3​>AsH3​>SbH3​

PH3​>NH3​>AsH3​>SbH3​

AsH3​>PH3​>NH3​>SbH3​

SbH3​>AsH3​>PH3​>NH3​

$N H_{3} > P H_{3} > A s H_{3} > S b H_{3}$

$P H_{3} > N H_{3} > A s H_{3} > S b H_{3}$

$A s H_{3} > P H_{3} > N H_{3} > S b H_{3}$

$S b H_{3} > A s H_{3} > P H_{3} > N H_{3}$