Copper sulphate solution, when added to an excess of ammonium hydroxide, forms a complex compound due to :

Question

Copper sulphate solution, when added to an excess of ammonium hydroxide, forms a complex compound due to : (A)  [Cu(NH3)2]2+  (B)  [Cu(NH3)4]2+  (C)  [Cu(NH3)6]2+  (D)  Cu2+

Tardigrade Admin · Accepted Answer

CuSO 4+ NH 4 OH longrightarrow [ Cu ( NH 3)4] SO 4+4 H 2 O or [ Cu ( NH 3)4]2+

Q. Copper sulphate solution, when added to an excess of ammonium hydroxide, forms a complex compound due to :

$[C u (N H_{3})_{2}]^{2 +}$

$[C u (N H_{3})_{4}]^{2 +}$

$[C u (N H_{3})_{6}]^{2 +}$

$C u^{2 +}$

$C u S O_{4} + N H_{4} O H ⟶ [C u (N H_{3})_{4}] S O_{4} + 4 H_{2} O$

or $[C u (N H_{3})_{4}]^{2 +}$

Q. Copper sulphate solution, when added to an excess of ammonium hydroxide, forms a complex compound due to :

[Cu(NH3​)2​]2+

[Cu(NH3​)4​]2+

[Cu(NH3​)6​]2+

Cu2+

CuSO4​+NH4​OH⟶[Cu(NH3​)4​]SO4​+4H2​O or [Cu(NH3​)4​]2+

$[C u (N H_{3})_{2}]^{2 +}$

$[C u (N H_{3})_{4}]^{2 +}$

$[C u (N H_{3})_{6}]^{2 +}$

$C u^{2 +}$

$C u S O_{4} + N H_{4} O H ⟶ [C u (N H_{3})_{4}] S O_{4} + 4 H_{2} O$

or $[C u (N H_{3})_{4}]^{2 +}$