Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54 mathringA. The value of lattice constant for this lattice is

Question

Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54 mathringA. The value of lattice constant for this lattice is (A)  1.27 mathringA (B)  5.08 mathringA (C)  2.54 mathringA (D)  3.59 mathringA

Tardigrade Admin · Accepted Answer

Interatomic spacing for a fcc lattice r=[((a/2))2+((a/2))2+(0)2]1 / 2=(a/√2) a being lattice constant. a=√2 r=√2 × 254=3.59 mathringA NOTE: Interatomic spacing is just the nearest neighbours distance.

Q. Copper has face-centered cubic $(f cc)$ lattice with interatomic spacing equal to $2.54 \overset{˚}{A}$ . The value of lattice constant for this lattice is

$1.27 \overset{˚}{A}$

$5.08 \overset{˚}{A}$

$2.54 \overset{˚}{A}$

$3.59 \overset{˚}{A}$

Interatomic spacing for a fcc lattice
$r = [(\frac{a}{2})^{2} + (\frac{a}{2})^{2} + (0)^{2}]^{1/2} = \frac{a}{2}$
a being lattice constant.
$a = 2 r = 2 \times 254 = 3.59 \overset{˚}{A}$
NOTE : Interatomic spacing is just the nearest neighbours distance.

Q. Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54A˚. The value of lattice constant for this lattice is

1.27A˚

5.08A˚

2.54A˚

3.59A˚