Question

Coordination number of Ni in ${\left[Ni{\left(C_2{O}_4\right)}_3\right]}^{4-}$ is

• A. 3
• B. 6
• C. 4
• D. 12

Answer 1

Answer: (B)

Coordination number of nickel in ${\left[Ni{\left(C_2{O}_4\right)}_3\right]}^{4-}$ is $6$ because $C_2{O}_4^{2-}$ is a bidentate ligand.