Coordination number of Ni in [ Ni ( C 2 O 4)3]4- is

Question

Coordination number of Ni in [ Ni ( C 2 O 4)3]4- is (A) 3 (B) 6 (C) 4 (D) 5

Tardigrade Admin · Accepted Answer

Coordination number of Ni in [ Ni ( C 2 O 4)3]4- is 6. This is because C 2 O 42- (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.

Q. Coordination number of $N i$ in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is

3

6

4

5

Coordination number of $N i$ in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is 6. This is because $C_{2} O_{4}^{2 -}$ (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.

Q. Coordination number of Ni in [Ni(C2​O4​)3​]4− is

3

6

4

5

Coordination number of Ni in [Ni(C2​O4​)3​]4− is 6. This is because C2​O42−​ (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.

Q. Coordination number of $N i$ in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is

Coordination number of $N i$ in $[N i (C_{2} O_{4})_{3}]^{4 -}$ is 6. This is because $C_{2} O_{4}^{2 -}$ (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.