Coordination number of Cr is six. A complex ion of Cr with C2O4 2-, en and superoxide ion, O2 - has the formula [Cr(C2O4)x(en)y(O2)z]-. The ratio x: y: z will be

Question

Coordination number of Cr is six. A complex ion of Cr with C2O4 2-, en and superoxide ion, O2 - has the formula [Cr(C2O4)x(en)y(O2)z]-. The ratio x: y: z will be (A) 1: 1: 1 (B) 1: 1: 2 (C) 1: 2: 2 (D) 2: 1: 1

Tardigrade Admin · Accepted Answer

x: y: z should be such that total charge = -1(i.e. charge on the complex ion). For (a), total charge = + 3 + 1 (-2) + 1(0) + 1 (-1) = 0 For (b), total charge = + 3 + 1 (-2) + 1(0) + 2(-1) = -1 Hence, (b) is correct.

Q. Coordination number of Cr is six. A complex ion of Cr with $C_{2} O_{4}^{2 -}$ , en and superoxide ion, $O_{2}^{-}$ has the formula $[C r (C_{2} O_{4})_{x} (e n)_{y} (O_{2})_{z}]^{-}$ . The ratio x : y : z will be

1 : 1 : 1

1 : 1 : 2

1 : 2 : 2

2 : 1 : 1

x : y : z should be such that total charge = -1(i.e. charge on the complex ion).
For (a), total charge = + 3 + 1 (-2) + 1(0) + 1 (-1) = 0
For (b), total charge = + 3 + 1 (-2) + 1(0) + 2(-1) = -1
Hence, (b) is correct.

Q. Coordination number of Cr is six. A complex ion of Cr with C2​O42−​, en and superoxide ion, O2−​ has the formula [Cr(C2​O4​)x​(en)y​(O2​)z​]−. The ratio x : y : z will be