1. Tardigrade
  2. Question
  3. Chemistry
  4. Coordination number of Cr is six. A complex ion of Cr with C2O4 2-, en and superoxide ion, O2 - has the formula [Cr(C2O4)x(en)y(O2)z]-. The ratio x: y: z will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Coordination number of Cr is six. A complex ion of Cr with $C_2O_4^{ 2-}$, en and superoxide ion, $O_2^ -$ has the formula $[Cr(C_2O_4)_x(en)_y(O_2)_z]^-$. The ratio x : y : z will be

Coordination Compounds

Solution:

x : y : z should be such that total charge = -1(i.e. charge on the complex ion).
For (a), total charge = + 3 + 1 (-2) + 1(0) + 1 (-1) = 0
For (b), total charge = + 3 + 1 (-2) + 1(0) + 2(-1) = -1
Hence, (b) is correct.