Consider the reaction at 300 K H 2( g )+ Cl 2( g ) arrow 2 HCl ( g ), Δ H °=-185 kJ mol -1 If 3 mole of H 2 completely react with 3 mol of Cl 2 to form HCl , Δ U ° of the reaction will be :

Question

Consider the reaction at 300 K H 2( g )+ Cl 2( g ) arrow 2 HCl ( g ), Δ H °=-185 kJ mol -1 If 3 mole of H 2 completely react with 3 mol of Cl 2 to form HCl , Δ U ° of the reaction will be : (A) Zero (B) - 185 kJ (C) -555 kJ (D) - 200 kJ

Tardigrade Admin · Accepted Answer

H 2+ Cl 2 longrightarrow 2 HCl Δ H =-185 kJ for 3 mole H 2 3 mole Cl 2 Δ H =-185 × 3=-555 kJ Δ U =Δ H

Q. Consider the reaction at $300 K$
$H_{2 (g)} + C l_{2 (g)} \to 2 H C l_{(g)}, Δ H^{\circ} = - 185 k J m o l^{- 1}$
If 3 mole of $H_{2}$ completely react with $3 m o l$ of $C l_{2}$ to form $H Cl, Δ U^{\circ}$ of the reaction will be :

Zero

- 185 kJ

-555 kJ

- 200 kJ

$H_{2} + C l_{2} ⟶ 2 H Cl Δ H = - 185 k J$
for $3$ mole $H_{2} & 3$ mole $C l_{2}$
$Δ H = - 185 \times 3 = - 555 k J$
$Δ U = Δ H$

Q. Consider the reaction at 300K H2(g)​+Cl2(g)​→2HCl(g)​,ΔH∘=−185kJmol−1 If 3 mole of H2​ completely react with 3mol of Cl2​ to form HCl,ΔU∘ of the reaction will be :