Consider the reaction at 300 K C 6 H 6(ℓ)+(15/2) O 2( g ) arrow 6 CO 2( g )+3 H 2 O (ℓ) Δ H =-3271 kJ What is Δ U for the combustion of 1.5 mole of benzene at 27° C ?

Question

Consider the reaction at 300 K C 6 H 6(ℓ)+(15/2) O 2( g ) arrow 6 CO 2( g )+3 H 2 O (ℓ) Δ H =-3271 kJ What is Δ U for the combustion of 1.5 mole of benzene at 27° C ? (A) -3267.25 kJ (B) -4900.88 kJ (C) -4906.5 kJ (D) -3274.75 kJ

Tardigrade Admin · Accepted Answer

Correct answer is (b) -4900.88 kJ

Q. Consider the reaction at 300K C6​H6​(ℓ)+215​O2​(g)→6CO2​(g)+3H2​O(ℓ)ΔH=−3271kJ What is ΔU for the combustion of 1.5 mole of benzene at 27∘C ?

-3267.25 kJ

-4900.88 kJ

-4906.5 kJ

-3274.75 kJ

Correct answer is (b) -4900.88 kJ

Q. Consider the reaction at $300 K$
$C_{6} H_{6} (ℓ) + \frac{15}{2} O_{2} (g) \to 6 C O_{2} (g) + 3 H_{2} O (ℓ) Δ H = - 3271 k J$
What is $Δ U$ for the combustion of $1.5$ mole of benzene at $2 7^{\circ} C$ ?