Consider the reaction, 2A + B → When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

Question

Consider the reaction, 2A + B → When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is (A) L mol-1 s-1 (B) no unit (C) mol-1 s-1 (D) s-1

Tardigrade Admin · Accepted Answer

2A+B arrow Products When conc. of B is doubled, the half life did not change, hence reaction is of first order w.r.t. B. When concentration of A is doubled, reaction rate is Hence over all order of reaction is 1 + 1 = 2 So, unit of rate constant mol-1 lit s-1. Hence, (1) is correct.

Q. Consider the reaction, $2 A + B \to$ When concentration of $B$ alone was doubled, the half-life did not change. When the concentration of $A$ alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

$L m o l^{- 1} s^{- 1}$

no unit

$m o l^{- 1} s^{- 1}$

$s^{- 1}$

Q. Consider the reaction, 2A+B→ When concentration of B alone was doubled, the half-life did not change. When the concentration of A alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

Lmol−1s−1

no unit

mol−1s−1

s−1

2A+B→ Products When conc. of B is doubled, the half life did not change, hence reaction is of first order w.r.t. B. When concentration of A is doubled, reaction rate is Hence over all order of reaction is 1+1=2 So, unit of rate constant mol−1lits−1. Hence, (1) is correct.

Q. Consider the reaction, $2 A + B \to$ When concentration of $B$ alone was doubled, the half-life did not change. When the concentration of $A$ alone was doubled, the rate increased by two times. The unit of rate constant for this reaction is

$L m o l^{- 1} s^{- 1}$

$m o l^{- 1} s^{- 1}$

$s^{- 1}$