Consider the junction diode as ideal. The value of current flowing through AB is

Question

Consider the junction diode as ideal. The value of current flowing through AB is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-a3cytraro5oc.png" /> (A) 0 A (B) 10- 2 A (C) 10- 1 A (D) 10- 3 A

Tardigrade Admin · Accepted Answer

I = (VA - VB/R) = (4 - (. - 6 .)/1000) = (10/1000) = 10- 2 A

Q. Consider the junction diode as ideal. The value of current flowing through $A B$ is

$0 A$

$1 0^{- 2} A$

$1 0^{- 1} A$

$1 0^{- 3} A$

$I = \frac{V _{A} - V _{B}}{R}$
$= \frac{4 - ( - 6 )}{1000}$
$= \frac{10}{1000} = 1 0^{- 2} A$

Q. Consider the junction diode as ideal. The value of current flowing through AB is

0A

10−2A

10−1A

10−3A