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Q. Consider the junction diode as ideal. The value of current flowing through $AB$ is

Question

NTA AbhyasNTA Abhyas 2020Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$I = \frac{V_{A} - V_{B}}{R}$
$= \frac{4 - \left(\right. - 6 \left.\right)}{1000}$
$= \frac{10}{1000} = 10^{- 2} \, A$