Question

Consider the hydrates ions of $T{i}^{2+},V^{2+},T{i}^{3+}$ and $S{c}^{3+}$. The correct order of their spin-only magnetic moments is :

• A. $S{c}^{3+}<T{i}^{3+}<T{i}^{2+}<V^{2+}$
• B. $T{i}^{3+}<T{i}^{2+}<S{c}^{3+}<V^{2+}$
• C. $S{c}^{3+}<T{i}^{3+}<V^{2+}<T{i}^{2+}$
• D. $V^{2+}<T{i}^{2+}<T{i}^{3+}<S{c}^{3+}$

Answer 1

Answer: (A)

$T{i}^{+2}=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^2$
unpaired electrons = $2$.
spin only magnetic moment $(\mu )=\sqrt{2(2+2)}$
$=\sqrt{8}$ B.M
$T{i}^{+3}=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^1$
unpaired electrons = 1
$\mu =\sqrt{1(1+2)}=\sqrt{3}$ B.M
$V^{+2}=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^3$
$\mu =\sqrt{3(3+2)}=\sqrt{15}$ B.M
$S{c}^{+3}=1s^{2}2s^{2}2p^{6}3s^{2}3p^6$
$\mu =0$