Consider the heterogeneous equilibrium in a closed container NH4HS (s) leftharpoons NH3 (g) + H2S(g) If more NH4HS is added to the equilibrium

Question

Consider the heterogeneous equilibrium in a closed container NH4HS (s) leftharpoons NH3 (g) + H2S(g) If more NH4HS is added to the equilibrium (A) Partial pressure of NH3 increases (B) Partial pressure of H2S increases (C) Total pressure in the container increases (D) No effect on partial pressure of NH3 and H2S

Tardigrade Admin · Accepted Answer

NH4HS (s) leftharpoons NH3(g) + H2S(g) Kp = NH3(g ) × H2S(g) Partial pressures of NH3 and H2O do not affect NH4HS(s) because NH4HS(s) is solid for solid active mass unity.

Q. Consider the heterogeneous equilibrium in a closed container
$N H_{4} H S (s) ⇌ N H_{3} (g) + H_{2} S (g)$
If more $N H_{4} H S$ is added to the equilibrium

Partial pressure of $N H_{3}$ increases

Partial pressure of $H_{2} S$ increases

Total pressure in the container increases

No effect on partial pressure of $N H_{3}$ and $H_{2} S$

$N H_{4} H S (s) ⇌ N H_{3 (g)} + H_{2} S (g)$
$K_{p} = N H_{3} (g) \times H_{2} S (g)$
Partial pressures of $N H_{3}$ and $H_{2} O$ do not affect $N H_{4} H S (s)$ because $N H_{4} H S (s)$ is solid for solid active mass unity.

Q. Consider the heterogeneous equilibrium in a closed container NH4​HS(s)⇌NH3​(g)+H2​S(g) If more NH4​HS is added to the equilibrium

Partial pressure of NH3​ increases

Partial pressure of H2​S increases