Consider the following two reactions: (i) Propene + H2 → Propane ; Δ H1 (ii) Cyclopropane + H2 Propane ; Δ H2 Then, Δ H2 - Δ H1 will be

Question

Consider the following two reactions: (i) Propene + H2 → Propane ; Δ H1 (ii) Cyclopropane + H2 Propane ; Δ H2 Then, Δ H2 - Δ H1 will be (A) 0 (B) 2BEC-C - BEC = C (C) BEC = C (D) 2BEC = C - BEC - C

Tardigrade Admin · Accepted Answer

CH3 - CH = CH2 + H2 → CH3 - CH2 - CH3; Δ H1= (BEC = C) +BEH-H) -(2BEC - H + BEC -C) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/2d9f8da0f865c2072eb4cf9312f4e0b0-.jpeg" /> Δ H2 = (BEC— C + BEH — H) - (2 × BEC— H) Δ H2-Δ H1 = 2BEC— C - BEC = C

Q. Consider the following two reactions :
(i) Propene $+ H_{2} \to$ Propane ; $Δ H_{1}$
(ii) Cyclopropane $+ H_{2}$ Propane ; $Δ H_{2}$
Then, $Δ H_{2} - Δ H_{1}$ will be

$0$

$2 B E_{C - C} - B E_{C = C}$

$B E_{C = C}$

$2 B E_{C = C} - B E_{C - C}$

$C H_{3} - C H = C H_{2} + H_{2} \to C H_{3} - C H_{2} - C H_{3}$ ;
$Δ H_{1} = (B E_{C = C)} + B E_{H - H}) - (2 B E_{C - H} + B E_{C - C})$

$Δ H_{2} = (B E_{C — C} + B E_{H — H}) - (2 \times B E_{C — H})$
$Δ H_{2} - Δ H_{1} = 2 B E_{C — C} - B E_{C = C}$

Q. Consider the following two reactions : (i) Propene +H2​→ Propane ; ΔH1​ (ii) Cyclopropane +H2​ Propane ; ΔH2​ Then, ΔH2​−ΔH1​ will be

0

2BEC−C​−BEC=C​

BEC=C​

2BEC=C​−BEC−C​

CH3​−CH=CH2​+H2​→CH3​−CH2​−CH3​; ΔH1​=(BEC=C)​+BEH−H​)−(2BEC−H​+BEC−C​) ΔH2​=(BEC—C​+BEH—H​)−(2×BEC—H​) ΔH2​−ΔH1​=2BEC—C​−BEC=C​

Q. Consider the following two reactions :
(i) Propene $+ H_{2} \to$ Propane ; $Δ H_{1}$
(ii) Cyclopropane $+ H_{2}$ Propane ; $Δ H_{2}$
Then, $Δ H_{2} - Δ H_{1}$ will be

$0$

$2 B E_{C - C} - B E_{C = C}$

$B E_{C = C}$

$2 B E_{C = C} - B E_{C - C}$

$C H_{3} - C H = C H_{2} + H_{2} \to C H_{3} - C H_{2} - C H_{3}$ ;
$Δ H_{1} = (B E_{C = C)} + B E_{H - H}) - (2 B E_{C - H} + B E_{C - C})$

$Δ H_{2} = (B E_{C — C} + B E_{H — H}) - (2 \times B E_{C — H})$
$Δ H_{2} - Δ H_{1} = 2 B E_{C — C} - B E_{C = C}$