1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the following statement: <math> <mrow> <mtext>(I)</mtext> <msub> <mo>CH</mo> <mn>3</mn> </msub> <msub> <mrow> <mover> <mtext>OCH</mtext> <mo>⊕</mo> </mover> </mrow> <mn>2</mn> </msub> </mrow></math> is more stable than <math> <msub> <mtext>CH</mtext> <mn>3</mn> </msub> <msub> <mrow> <mover> <mtext>CH</mtext> <mo>⊕</mo> </mover> </mrow> <mn>2</mn> </msub> </math> <math> <mrow> <mtext>(II)</mtext> <msub> <mo>Me</mo> <mn>3</mn> </msub> <mrow> <mover> <mtext>C</mtext> <mo>⊕</mo> </mover> </mrow> </mrow></math> is more stable than <math> <msub> <mtext>CH</mtext> <mn>3</mn> </msub> <msub> <mrow> <mrow> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> <mover> <mtext>CH</mtext> <mo>⊕</mo> </mover> </mrow> </mrow> <mn>2</mn> </msub> </math> <math> <mrow> <mtext>(III)</mtext> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> <mrow> <mrow> <mo>=</mo> <mtext>CH</mtext> <mo>-</mo> <msub> <mrow> <mrow> <mover> <mtext>CH</mtext> <mo>⊕</mo> </mover> </mrow> </mrow> <mn>2</mn> </msub> </mrow> </mrow> </mrow></math> is more stable than <math> <msub> <mtext>CH</mtext> <mn>3</mn> </msub> <mrow> <mrow> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> <mover> <mrow> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> </mrow> <mo>⊕</mo> </mover> </mrow> </mrow> </math> <math> <mrow> <mtext>(IV)</mtext> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> <mrow> <mrow> <mo>=</mo> <mover> <mtext>CH</mtext> <mo>⊕</mo> </mover> </mrow> </mrow> </mrow></math> is more stable than <math> <msub> <mtext>CH</mtext> <mn>3</mn> </msub> <mrow> <mrow> <mspace></mspace> <mover> <mrow> <msub> <mtext>CH</mtext> <mn>2</mn> </msub> </mrow> <mo>⊕</mo> </mover> </mrow> </mrow> </math> Of these statement:

Q. Consider the following statement :
(I) CH 3 OCH 2 is more stable than CH 3 CH 2
(II) Me 3 C is more stable than CH 3 CH 2 CH 2
(III) CH 2 = CH - CH 2 is more stable than CH 3 CH 2 CH 2
(IV) CH 2 = CH is more stable than CH 3 CH 2
Of these statement:

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Solution:

(I) CH 3 O CH 2 is more stable than CH 3 CH 2 , becausse of +M-effect of CH 3 - O - .
(II) Me 3 C H is more stable than CH 3 - CH 2 - CH 2 ,
because Me 3 C have more 2-hydrogen atoms than CH 3 CH 2 CH 2 , so, it is more stable, due to greater hyperconjugation.
(III) The positive charge is delocalised in C H 2 =CHC H 2 , so more stable than, CH 3 CH 2 CH 2 .
(IV) CH 2 = CH will be less stable than CH 3 - CH 2 as positive charge is less stable on double bonded 'C' than on single bonded 'C'.