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Tardigrade
Question
Chemistry
Consider the following reactions: (i) C2O42 - arrow CO2 (ii) SO42 - arrow SO32 - (iii) MnO42 - arrow MnO4- (iv) Fe3 + arrow Fe2 + Choose the correct answer: -
Q. Consider the following reactions:
(i)
C
2
O
4
2
−
→
C
O
2
(ii)
S
O
4
2
−
→
S
O
3
2
−
(iii)
M
n
O
4
2
−
→
M
n
O
4
−
(iv)
F
e
3
+
→
F
e
2
+
Choose the correct answer: -
1861
228
NTA Abhyas
NTA Abhyas 2020
Redox Reactions
Report Error
A
(
i
)
&
(
ii
)
shows oxidation
7%
B
(
iii
)
&
(
i
v
)
shows reduction
23%
C
(
i
)
&
(
iii
)
shows oxidation
57%
D
(
iii
)
&
(
i
v
)
shows oxidation
13%
Solution:
In
C
2
O
4
2
−
→
C
O
2
oxidation number of carbon change from
+
3
t
o
+
4
.
In
S
O
4
2
−
→
S
O
3
2
−
oxidation number of sulphur change from
+
6
t
o
+
4
.
In
M
n
O
4
2
−
→
M
n
O
4
−
oxidation number of Mn change from
+
6
t
o
+
7
.
In
F
e
3
+
→
F
e
2
+
oxidation number of carbon change from +3 to +2.