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Tardigrade
Question
Chemistry
Consider the following reaction xMnO4-+yC2O42 -+zH+ arrow xMn2 ++2yCO2+(z/2)H2O The values of x, y and z in the reaction are, respectively
Q. Consider the following reaction
x
M
n
O
4
−
+
y
C
2
O
4
2
−
+
z
H
+
→
x
M
n
2
+
+
2
y
C
O
2
+
2
z
H
2
O
The values of x, y and z in the reaction are, respectively
203
188
NTA Abhyas
NTA Abhyas 2022
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A
5, 2 and 8
B
2, 5 and 8
C
2, 5 and 16
D
5, 2 and 16
Solution:
2
M
n
O
4
−
+
5
C
2
O
4
2
−
+
16
H
+
→
2
M
n
2
+
+
10
C
O
2
+
8
H
2
O
Here
x
=
2
,
y
=
5
and
z
=
16
.