Question

Consider the following reaction
$xMnO_{4}^{-}+yC_{2}O_{4}^{2 -}+zH^{+} \rightarrow xMn^{2 +}+2yCO_{2}+\frac{z}{2}H_{2}O$
The values of x, y and z in the reaction are, respectively

• A. 5, 2 and 8
• B. 2, 5 and 8
• C. 2, 5 and 16
• D. 5, 2 and 16

Answer 1

Answer: (C)

$2MnO_{4}^{-}+5C_{2}O_{4}^{2 -}+16H^{+} \rightarrow 2Mn^{2 +}+10CO_{2}+8H_{2}O$
Here $x = 2, y = 5$ and $z = 16$.