Consider the following reaction, Select the incorrect statement.

Question

Consider the following reaction,

Select the incorrect statement. (A) It is not a disproportionation reaction. (B) It is intramolecular redox reaction. (C) OH- is a reducing as well as oxidising agent. (D)

is a reducing as well as oxidising agent.

Tardigrade Admin · Accepted Answer

One CHO is oxidised to COO- and one CHO is reduced to CH2OH. Thus, it is not a disproportionation reaction. It is intramolecular redox reaction. Thus, options (a) and (b) are true and <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6eb4528618e85b1fea40280aca2dee9e-.jpeg" /> is reducing as well as oxidising agent. Thus, (d) is also true. Thus, (c) is incorrect.

Q. Consider the following reaction,

Select the incorrect statement.

It is not a disproportionation reaction.

It is intramolecular redox reaction.

$O H^{-}$ is a reducing as well as oxidising agent.

is a reducing as well as oxidising agent.

One $C H O$ is oxidised to $CO O^{-}$ and one $C H O$ is reduced to $C H_{2} O H$ .
Thus, it is not a disproportionation reaction. It is intramolecular redox reaction. Thus, options (a) and (b) are true and is reducing as well as oxidising agent. Thus, (d) is also true. Thus, (c) is incorrect.

Q. Consider the following reaction, Select the incorrect statement.

It is not a disproportionation reaction.

It is intramolecular redox reaction.

OH− is a reducing as well as oxidising agent.

is a reducing as well as oxidising agent.

One CHO is oxidised to COO− and one CHO is reduced to CH2​OH. Thus, it is not a disproportionation reaction. It is intramolecular redox reaction. Thus, options (a) and (b) are true and is reducing as well as oxidising agent. Thus, (d) is also true. Thus, (c) is incorrect.

Q. Consider the following reaction,

Select the incorrect statement.

$O H^{-}$ is a reducing as well as oxidising agent.

One $C H O$ is oxidised to $CO O^{-}$ and one $C H O$ is reduced to $C H_{2} O H$ .
Thus, it is not a disproportionation reaction. It is intramolecular redox reaction. Thus, options (a) and (b) are true and is reducing as well as oxidising agent. Thus, (d) is also true. Thus, (c) is incorrect.