Question

Consider the following reaction ${\underset{pd-BaS{O}_4}{\overset{H_2}{\to }}}^{\prime }{A}^{\prime }$
The product 'A' is -

• A. $C_6{H}_{5}OH$
• B. $C_6{H}_{5}COC{H}_3$
• C. $C_6{H}_{5}Cl$
• D. $C_6{H}_{5}CHO$

Answer 1

Answer: (D)

In Rosenmund reaction, acid chloride reacts with $H_2$ in the presence of $Pd/BaS{O}_4$ to yield aldehyde.