Consider the following liquid-vapour equilibrium Liquid leftharpoons Vapour Which of the following relations is correct ?

Question

Consider the following liquid-vapour equilibrium Liquid leftharpoons Vapour Which of the following relations is correct ? (A)  (d In P/dT) = ( - Δ Hv/RT) (B)  (d In P/dT2) = ( - Δ Hv/T2) (C)  (d In P/dT) = ( Δ Hv/RT2) (D)  (d In G/dT2) = ( Δ Hv/RT2)

Tardigrade Admin · Accepted Answer

Acc. To Clausius Claperon equation P = Ae(-Δ H/RT) l n P = l n A + ln e(-Δ H/RT) ⇒ lnp = lnA - (Δ H/RT) lne or lnp = lnA - (Δ H/RT) (d/dT) (ln P) = 0 + (-Δ H/R) (d/dT) (T-1) (d/dT) lnP = (Δ HV/RT2)

Q. Consider the following liquid-vapour equilibrium Liquid $⇌$ Vapour
Which of the following relations is correct ?

$\frac{d I n P}{d T} = \frac{- Δ H _{v}}{RT}$

$\frac{d I n P}{d T ^{2}} = \frac{- Δ H _{v}}{T ^{2}}$

$\frac{d I n P}{d T} = \frac{Δ H _{v}}{R T ^{2}}$

$\frac{d I n G}{d T ^{2}} = \frac{Δ H _{v}}{R T ^{2}}$

Q. Consider the following liquid-vapour equilibrium Liquid ⇌ Vapour Which of the following relations is correct ?

dTdInP​=RT−ΔHv​​

dT2dInP​=T2−ΔHv​​

dTdInP​=RT2ΔHv​​

dT2dInG​=RT2ΔHv​​

Acc. To Clausius Claperon equation P=AeRT−ΔH​ lnP=lnA+lneRT−ΔH​⇒lnp=lnA−RTΔH​lne or lnp=lnA−RTΔH​ dTd​(lnP)=0+R−ΔH​dTd​(T−1) dTd​lnP=RT2ΔHV​​

Q. Consider the following liquid-vapour equilibrium Liquid $⇌$ Vapour
Which of the following relations is correct ?

$\frac{d I n P}{d T} = \frac{- Δ H _{v}}{RT}$

$\frac{d I n P}{d T ^{2}} = \frac{- Δ H _{v}}{T ^{2}}$

$\frac{d I n P}{d T} = \frac{Δ H _{v}}{R T ^{2}}$

$\frac{d I n G}{d T ^{2}} = \frac{Δ H _{v}}{R T ^{2}}$