Q.
Consider the following fusion reaction: 1H2+1H2→2He4. If 20MeV of energy is released per fusion reaction and mass of 1H2 consumed per day is 0.1g, then what is the power of the reactor (in MW)?
(Give answer in integer value)
Let P be the power.
Energy produced =P×24×36×100
Energy released per fusion reaction =20MeV=32×10−13J
Energy released per 1H2 atom =32×10−13J
Number of 1H2 atoms used is N=32×10−13P×24×36×100
Mass of 6×1023 atoms =2g 6×10232×32×10−13P×24×3600 =0.1g P=1MW