Question

Consider the following equations:
$2F{e}^{2+}+H_2{O}_2\to xA+yB$ (in basic medium)
$2Mn{O}_4^{-}+6H^{+}+5H_2{O}_2\to x^{\prime }C+y^{\prime }D+z^{\prime }E$ (in acidic medium)
The sum of the stoichiometric coefficients
$x,y,x^{\prime },y^{\prime }$ and $z^{\prime }$ for products $A,B,C,D$ and $E$, respectively, is ___

Answer 1

Answer: 19

$\left[F{e}^{2+}\to F{e}^{3+}+e^{-}\right]\times 2$

$\frac{H_2{O}_2+2e^{-}\to 2H{O}^{\ominus }}{2F{e}^{2+}+H_2{O}_2\to 2F{e}^{3+}+2H{O}_{\text{qω }}^{\ominus }}$

$x=2y=2$

$\left[8H^{+}+Mn{O}_4^{-}+5e^{-}\to M{n}^{2+}+4H_{2}O\right]\times 2$

$\left[H_2{O}_2\to O_{2(g)}+2H^{+}+2e^{-}\right]\times 5$

$\Rightarrow 16H^{+}+2Mn{O}_4^{-}+5H_2{O}_2$

$\to 2M{n}^{2+}+8H_{2}O+5O_{2(g)}+10H^{+}$

$\Rightarrow 6H^{+}+2Mn{O}_4^{-}+5H_2{O}_2$

$\to 2M{n}^{2+}+8H_{2}O+5O_{2(g)}$

So $x^{\prime }=2y^{\prime }=8z^{\prime }=5$

so $x+y+x^{\prime }+y^{\prime }+z^{\prime }$

$\Rightarrow 2+2+2+8+5$

$\Rightarrow 19$