Consider the following electrodes P = Zn 2+(0.0001 M ) / Zn Q = Zn 2+(0.1 M ) / Zn R = Zn 2+(0.01 M ) / Zn S = Zn 2+(0.001 M ) / Zn E ° Zn / Zn 2+=-0.76 V Electrode potentials of the above electrodes in volts are in the order

Question

Consider the following electrodes P = Zn 2+(0.0001 M ) / Zn Q = Zn 2+(0.1 M ) / Zn R = Zn 2+(0.01 M ) / Zn S = Zn 2+(0.001 M ) / Zn E ° Zn / Zn 2+=-0.76 V Electrode potentials of the above electrodes in volts are in the order (A) P > S > R > Q (B) S>R>Q>P (C) Q > R > S > P (D) P > Q > R > S

Tardigrade Admin · Accepted Answer

Electrode potential is directly proportional to concentration of Zn 2 ions.

Q. Consider the following electrodes $P = Z n^{2 +} (0.0001 M) / Z n Q = Z n^{2 +} (0.1 M) / Z n$ $R = Z n^{2 +} (0.01 M) / Z n S = Z n^{2 +} (0.001 M) / Z n$ $E^{\circ} Z n / Z n^{2 +} = - 0.76 V$ Electrode potentials of the above electrodes in volts are in the order

$P > S > R > Q$

$S > R > Q > P$

$Q > R > S > P$

$P > Q > R > S$

Electrode potential is directly proportional to concentration of $Z n^{2}$ ions.

Q. Consider the following electrodes P=Zn2+(0.0001M)/ZnQ=Zn2+(0.1M)/Zn R=Zn2+(0.01M)/ZnS=Zn2+(0.001M)/Zn E∘Zn/Zn2+=−0.76V Electrode potentials of the above electrodes in volts are in the order

P>S>R>Q

S>R>Q>P

Q>R>S>P

P>Q>R>S