1. Tardigrade
  2. Question
  3. Chemistry
  4. Consider the following electrodes P = Zn 2+(0.0001 M ) / Zn Q = Zn 2+(0.1 M ) / Zn R = Zn 2+(0.01 M ) / Zn S = Zn 2+(0.001 M ) / Zn E ° Zn / Zn 2+=-0.76 V Electrode potentials of the above electrodes in volts are in the order

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Q. Consider the following electrodes $P = Zn ^{2+}(0.0001 M ) / Zn \quad Q = Zn ^{2+}(0.1 M ) / Zn$ $R = Zn ^{2+}(0.01 M ) / Zn \quad S = Zn ^{2+}(0.001 M ) / Zn$ $E ^{\circ} Zn / Zn ^{2+}=-0.76\, V$ Electrode potentials of the above electrodes in volts are in the order

KCETKCET 2021Electrochemistry

Solution:

Electrode potential is directly proportional to concentration of $Zn ^{2}$ ions.