Consider the following dioxide of group 14 1. CO2 2. SiO2 3. GeO2 4. SnO2 5. PbO2 The basicity of the dioxide alters in the order

Question

Consider the following dioxide of group 14 1. CO2 2. SiO2 3. GeO2 4. SnO2 5. PbO2 The basicity of the dioxide alters in the order (A) CO2>SiO2>GeO2>SnO2>PbO2 (B) CO2 < SiO2 < GeO2 < SnO2 < PbO2 (C) CO2 < SiO2 < GeO2 < PbO2 < SnO2 (D) CO2 < SiO2 < SnO2 < PbO2 < GeO2

Tardigrade Admin · Accepted Answer

The basicity of the dioxide alters in the order

C O_{2} < S i O_{2} < G e O_{2} < S n O_{2} < P b O_{2}

The basicity increases on moving down the group. Thus,

C O_{2}

and

S i O_{2}

are purely acidic.

G e O_{2}

is not as strongly acidic as

S i O_{2}

. It is weakly acidic and weakly basic.

S n O_{2}

and

P b O_{2}

are definitely amphoteric.

Q. Consider the following dioxide of group 14
$1.$ $C O_{2}$
$2.$ $S i O_{2}$
$3.$ $G e O_{2}$
$4.$ $S n O_{2}$
$5.$ $P b O_{2}$
The basicity of the dioxide alters in the order

$C O_{2} > S i O_{2} > G e O_{2} > S n O_{2} > P b O_{2}$

$C O_{2} < S i O_{2} < G e O_{2} < S n O_{2} < P b O_{2}$

$C O_{2} < S i O_{2} < G e O_{2} < P b O_{2} < S n O_{2}$

$C O_{2} < S i O_{2} < S n O_{2} < P b O_{2} < G e O_{2}$

Q. Consider the following dioxide of group 14 1. CO2​ 2. SiO2​ 3. GeO2​ 4. SnO2​ 5. PbO2​ The basicity of the dioxide alters in the order

CO2​>SiO2​>GeO2​>SnO2​>PbO2​

CO2​<SiO2​<GeO2​<SnO2​<PbO2​

CO2​<SiO2​<GeO2​<PbO2​<SnO2​

CO2​<SiO2​<SnO2​<PbO2​<GeO2​

Q. Consider the following dioxide of group 14
$1.$ $C O_{2}$
$2.$ $S i O_{2}$
$3.$ $G e O_{2}$
$4.$ $S n O_{2}$
$5.$ $P b O_{2}$
The basicity of the dioxide alters in the order

$C O_{2} > S i O_{2} > G e O_{2} > S n O_{2} > P b O_{2}$

$C O_{2} < S i O_{2} < G e O_{2} < S n O_{2} < P b O_{2}$

$C O_{2} < S i O_{2} < G e O_{2} < P b O_{2} < S n O_{2}$

$C O_{2} < S i O_{2} < S n O_{2} < P b O_{2} < G e O_{2}$