2KClO)3+1+5−2⟶2KCl+1−1+3O20
(a) The oxidation number of K does not change, thus K undergoes neither reduction nor oxidation.
(b) The oxidation number of chlorine decreases from +5 in KClO3 to −1 in KCl, hence Cl undergoes reduction.
(c) Since, oxidation number of oxygen increases from −2 in KClO3 to 0 in O2, so oxygen is oxidised.
(d) This statement is not correct because Cl is undergoing reduction and O is undergoing oxidation.
Therefore, statement (b) is true about the given reaction.