Consider the equilibria (1) and (2) with equilibrium constants K1 and K2, respectively. SO2(g) + 1/2 O2(g) SO3(g) ldots (i) 2SO3(g) 2SO2(g) + O2(g) ldots (ii) K1 and K2 are related as

Question

Consider the equilibria (1) and (2) with equilibrium constants K1 and K2, respectively. SO2(g) + 1/2 O2(g) <=> SO3(g) ldots (i) 2SO3(g) <=> 2SO2(g) + O2(g) ldots (ii) K1 and K2 are related as (A) 2K1=K22 (B) K21=(1/K2) (C) K22=(1/K1) (D) K2=(2/K21)

Tardigrade Admin · Accepted Answer

If the equation is multiplied by the factor

2

, then equilibrium constant will be the square of the equilibrium constant of that equation. If the reaction is reversed, the value of equilibrium constant is inversed.

S O_{2} (g) + 1/2 O_{2} (g) S O_{3} (g) \dots

(i)

2 S O_{3} (g) 2 S O_{2} (g) + O_{2} (g) \dots

(ii)
Eq. (ii) can be obtained by multiplying
Eq. (i) by 2 and the reversing it.
Thus,

K_{2} = \frac{1}{K _{1}^{2}} \Rightarrow K_{1}^{2} = \frac{1}{K _{2}}

Q. Consider the equilibria $(1)$ and $(2)$ with equilibrium constants $K_{1}$ and $K_{2}$ , respectively.
$S O_{2} (g) + 1/2 O_{2} (g) S O_{3} (g) \dots$ (i)
$2 S O_{3} (g) 2 S O_{2} (g) + O_{2} (g) \dots$ (ii)
$K_{1}$ and $K_{2}$ are related as

$2 K_{1} = K_{2}^{2}$

$K_{1}^{2} = \frac{1}{K ^{2}}$

$K_{2}^{2} = \frac{1}{K _{1}}$

$K_{2} = \frac{2}{K _{1}^{2}}$

Q. Consider the equilibria (1) and (2) with equilibrium constants K1​ and K2​, respectively. SO2​(g)+1/2O2​(g)​SO3​(g)…(i) 2SO3​(g)​2SO2​(g)+O2​(g)… (ii) K1​ and K2​ are related as

2K1​=K22​

K12​=K21​

K22​=K1​1​

K2​=K12​2​

Q. Consider the equilibria $(1)$ and $(2)$ with equilibrium constants $K_{1}$ and $K_{2}$ , respectively.
$S O_{2} (g) + 1/2 O_{2} (g) S O_{3} (g) \dots$ (i)
$2 S O_{3} (g) 2 S O_{2} (g) + O_{2} (g) \dots$ (ii)
$K_{1}$ and $K_{2}$ are related as

$2 K_{1} = K_{2}^{2}$

$K_{1}^{2} = \frac{1}{K ^{2}}$

$K_{2}^{2} = \frac{1}{K _{1}}$

$K_{2} = \frac{2}{K _{1}^{2}}$