Consider the complete combustion of butane, the amount of butane utilized to produce 72.0 g of water is × 10-1 g. (in nearest integer)

Question

Consider the complete combustion of butane, the amount of butane utilized to produce 72.0 g of water is × 10-1 g. (in nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

C 4 H 10+(13/2) O 2 arrow 4 CO 2+5 H 2 O Moles of H 2 O =(72/18)=4 Moles of C4 H10 used =(1/5) × 4 Weight of C4 H10 used =(4/5) × 58 =46.4 gm

Q. Consider the complete combustion of butane, the amount of butane utilized to produce $72.0 g$ of water is________ $\times 1 0^{- 1} g$ . (in nearest integer)

$C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O$
Moles of $H_{2} O = \frac{72}{18} = 4$
Moles of $C_{4} H_{10}$ used $= \frac{1}{5} \times 4$
Weight of $C_{4} H_{10}$ used $= \frac{4}{5} \times 58$
$= 46.4 g m$

Q. Consider the complete combustion of butane, the amount of butane utilized to produce 72.0g of water is________ ×10−1g. (in nearest integer)

C4​H10​+213​O2​→4CO2​+5H2​O Moles of H2​O=1872​=4 Moles of C4​H10​ used =51​×4 Weight of C4​H10​ used =54​×58 =46.4gm

Q. Consider the complete combustion of butane, the amount of butane utilized to produce $72.0 g$ of water is________ $\times 1 0^{- 1} g$ . (in nearest integer)

$C_{4} H_{10} + \frac{13}{2} O_{2} \to 4 C O_{2} + 5 H_{2} O$
Moles of $H_{2} O = \frac{72}{18} = 4$
Moles of $C_{4} H_{10}$ used $= \frac{1}{5} \times 4$
Weight of $C_{4} H_{10}$ used $= \frac{4}{5} \times 58$
$= 46.4 g m$