Consider the circuit shown. If all the cells have negligible internal resistance, what will be the current through the 2 Ω resistor when steady state is reached?

Question

Consider the circuit shown. If all the cells have negligible internal resistance, what will be the current through the 2 Ω resistor when steady state is reached? (A) 0.66 A (B) 0.29 A (C) 0 A (D) 0.14 A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/55b6e4e487f25abf5a034351d338bb23-.png" /> Equivalent emf of loop (2-2) V=0 ∴ I=0 2-8 I-8 I-2=0 -8 I=0 I=0

Q. Consider the circuit shown. If all the cells have negligible internal resistance, what will be the current through the $2Ω$ resistor when steady state is reached?

0.66 A

0.29 A

0 A

0.14 A

Equivalent emf of loop
$(2 - 2) V = 0$
$∴ I = 0$
$2 - 8 I - 8 I - 2 = 0$
$- 8 I = 0$
$I = 0$

Q. Consider the circuit shown. If all the cells have negligible internal resistance, what will be the current through the 2Ω resistor when steady state is reached?

0.66 A

0.29 A

0 A

0.14 A

Equivalent emf of loop (2−2)V=0 ∴I=0 2−8I−8I−2=0 −8I=0 I=0

Q. Consider the circuit shown. If all the cells have negligible internal resistance, what will be the current through the $2Ω$ resistor when steady state is reached?

Equivalent emf of loop
$(2 - 2) V = 0$
$∴ I = 0$
$2 - 8 I - 8 I - 2 = 0$
$- 8 I = 0$
$I = 0$