Consider the acidity of the carboxylic acids (i) PhCOOH (ii) o-NO2C6H4COOH (iii) p-NO2C6H4COOH (iv) m-NO2C6H4COOH Which of the following orders is correct?

Question

Consider the acidity of the carboxylic acids (i) PhCOOH (ii) o-NO2C6H4COOH (iii) p-NO2C6H4COOH (iv) m-NO2C6H4COOH Which of the following orders is correct? (A) (i) > (ii) > (iii) > (iv) (B) (ii) > (iv) > (iii) > (i) (C) (ii) > (iv) > (i) > (iii) (D) (ii) > (iii) > (iv) > (i)

Tardigrade Admin · Accepted Answer

-NO2 group at any position shows electron withdrawing effect, thus acid strength is increased, but o-nitro benzoate ion is stabilised by intramoiecuiar H-bonding like forces, hence its acid strength is maximum. Thus, the order of acid strength is (ii) > (iii) > (iv) > (i).

Q. Consider the acidity of the carboxylic acids
(i) PhCOOH (ii) $o - N O_{2} C_{6} H_{4} COO H$ (iii) $p - N O_{2} C_{6} H_{4} COO H$ (iv) $m - N O_{2} C_{6} H_{4} COO H$
Which of the following orders is correct?

(i) > (ii) > (iii) > (iv)

(ii) > (iv) > (iii) > (i)

(ii) > (iv) > (i) > (iii)

(ii) > (iii) > (iv) > (i)

$- N O_{2}$ group at any position shows electron withdrawing effect, thus acid strength is increased, but o-nitro benzoate ion is stabilised by intramoiecuiar H-bonding like forces, hence its acid strength is maximum.
Thus, the order of acid strength is (ii) > (iii) > (iv) > (i).

Q. Consider the acidity of the carboxylic acids (i) PhCOOH (ii) o−NO2​C6​H4​COOH (iii) p−NO2​C6​H4​COOH (iv) m−NO2​C6​H4​COOH Which of the following orders is correct?