Consider the 3 numbers 60,72 and 128 , then which of following is/are correct?

Question

Consider the 3 numbers 60,72 and 128 , then which of following is/are correct? (A) L.C.M of (60,72,128)=12160 (B) L.C.M of (60,72,128)=11500 (C) H.C.F of (60,72,128)=2 (D) H.C.F of (60,72,128)=4

Tardigrade Admin · Accepted Answer

Given: 3 numbers are 60,72,128 60 =22 × 3 × 5 72 =23 × 32 128 =26 (a) ∴ LCM of (60,72,128)=26 × 32 × 5 =12160 (d) H.C.F of (60,72,128)=22=4

Q. Consider the 3 numbers 60,72 and 128 , then which of following is/are correct?

L.C.M of $(60, 72, 128) = 12160$

L.C.M of $(60, 72, 128) = 11500$

H.C.F of $(60, 72, 128) = 2$

H.C.F of $(60, 72, 128) = 4$

Given: 3 numbers are $60, 72, 128$
$60 = 2^{2} \times 3 \times 5$
$72 = 2^{3} \times 3^{2}$
$128 = 2^{6}$
(a) $∴$ LCM of $(60, 72, 128) = 2^{6} \times 3^{2} \times 5$ $= 12160$
(d) H.C.F of $(60, 72, 128) = 2^{2} = 4$

Q. Consider the 3 numbers 60,72 and 128 , then which of following is/are correct?

L.C.M of (60,72,128)=12160

L.C.M of (60,72,128)=11500

H.C.F of (60,72,128)=2

H.C.F of (60,72,128)=4

Given: 3 numbers are 60,72,128 60=22×3×5 72=23×32 128=26 (a) ∴ LCM of (60,72,128)=26×32×5 =12160 (d) H.C.F of (60,72,128)=22=4

L.C.M of $(60, 72, 128) = 12160$

L.C.M of $(60, 72, 128) = 11500$

H.C.F of $(60, 72, 128) = 2$

H.C.F of $(60, 72, 128) = 4$

Given: 3 numbers are $60, 72, 128$
$60 = 2^{2} \times 3 \times 5$
$72 = 2^{3} \times 3^{2}$
$128 = 2^{6}$
(a) $∴$ LCM of $(60, 72, 128) = 2^{6} \times 3^{2} \times 5$ $= 12160$
(d) H.C.F of $(60, 72, 128) = 2^{2} = 4$