Consider single slit experiment of diffraction of light. If the light of wavelength 5000 mathringA fall on a slit of width 1 μ m then the angular width of central maximum is

Question

Consider single slit experiment of diffraction of light. If the light of wavelength 5000 mathringA fall on a slit of width 1 μ m then the angular width of central maximum is (A) 30°  (B) 15°  (C) 60°  (D) None of these

Tardigrade Admin · Accepted Answer

dsin θ =λ sin θ =(λ /d) For first minima =(5 × 10- 7/10- 6) sin θ =(5/10) θ =30° Angular width of first minima <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-ne6iabpx59mp4dyl.jpg" /> 2θ =60°

Q. Consider single slit experiment of diffraction of light. If the light of wavelength $5000 \overset{˚}{A}$ fall on a slit of width $1 μ m$ then the angular width of central maximum is

$3 0^{\circ}$

$1 5^{\circ}$

$6 0^{\circ}$

None of these

$d s in θ = λ$
$s in θ = \frac{λ}{d}$
For first minima
$= \frac{5 \times 1 0 ^{- 7}}{1 0 ^{- 6}}$
$s in θ = \frac{5}{10}$
$θ = 3 0^{\circ}$ Angular width of first minima

$2 θ = 6 0^{\circ}$

Q. Consider single slit experiment of diffraction of light. If the light of wavelength 5000A˚ fall on a slit of width 1μm then the angular width of central maximum is

30∘

15∘

60∘