Consider following reactions in equilibrium concentration 0.01 M of every species (I) PCl5(g) leftharpoons PCl3(g) + Cl2(g) (II) 2HI(g) leftharpoons H2(g) + I2(g) (III) N2(g) + 3H2(g) leftharpoons 2NH3(g) Extent of the reactions taking place is

Question

Consider following reactions in equilibrium concentration 0.01 M of every species (I) PCl5(g) leftharpoons PCl3(g) + Cl2(g) (II) 2HI(g) leftharpoons H2(g) + I2(g) (III) N2(g) + 3H2(g) leftharpoons 2NH3(g) Extent of the reactions taking place is (A) I > II > III (B) I < II < III (C) II< III< I (D) III < I < II

Tardigrade Admin · Accepted Answer

Extent of reaction can be calculated by the value of

K_{c}

. The higher value of

K_{c}

the larger the extent of reaction.

(I) PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)

\frac{[ PC l _{3} ] [ C l _{2} ]}{[ PC l _{5} ]} = \frac{0.01 \times 0.01}{0.01} = 0.01

(II) 2 H I ⇌ H_{2} + I_{2}, K_{C} = \frac{[ H _{2} ] [ I _{2} ]}{[ H I ] ^{2}}

= \frac{( 0.01 ) ( 0.01 )}{( 0.01 ) ^{2}} = 1

(III) N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

K_{c} = \frac{[ N H _{3} ] ^{2}}{[ N _{2} [ H _{2} ] ^{3}} = \frac{( 0.01 ) ^{2}}{( 0.01 ) ^{4}} \frac{1}{0.01 \times 0.01} = 10000

Extent of reaction

I < II < III

Q. Consider following reactions in equilibrium concentration $0.01$ M of every species
$(I) PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)$
$(II) 2 H I (g) ⇌ H_{2} (g) + I_{2} (g)$
$(III) N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
Extent of the reactions taking place is

$I > II > III$

$I < II < III$

$II < III < I$

$III < I < II$

Q. Consider following reactions in equilibrium concentration 0.01 M of every species (I)PCl5​(g)⇌PCl3​(g)+Cl2​(g) (II)2HI(g)⇌H2​(g)+I2​(g) (III)N2​(g)+3H2​(g)⇌2NH3​(g) Extent of the reactions taking place is

I>II>III

I<II<III

II<III<I

III<I<II

Q. Consider following reactions in equilibrium concentration $0.01$ M of every species
$(I) PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)$
$(II) 2 H I (g) ⇌ H_{2} (g) + I_{2} (g)$
$(III) N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
Extent of the reactions taking place is

$I > II > III$

$I < II < III$

$II < III < I$

$III < I < II$