Consider first two cells in series as shown in figure the potential difference between the terminals A and C of the combination is

Question

Consider first two cells in series as shown in figure the potential difference between the terminals A and C of the combination is (A) VA C=ε1-Ir1 (B) VA C=ε2-I r2 (C) VA C=ε eq -I r eq  (D) VA C=2 ε eq -I r eq

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cefc50deadccce5118b71ab08b3f3a3d-.png" /> VA C=V(A)-V(C) =[V(A)-V(B)]+[V(B)-V(C)] =ε1-I r1+ε2-I r2 =(ε1+ε2)-I(r1+r2)=ε eq -I r eq

Q. Consider first two cells in series as shown in figure the potential difference between the terminals $A$ and $C$ of the combination is

$V_{A C} = ε_{1} - I r_{1}$

$V_{A C} = ε_{2} - I r_{2}$

$V_{A C} = ε_{e q} - I r_{e q}$

$V_{A C} = 2 ε_{e q} - I r_{e q}$

$V_{A C} = V (A) - V (C) = [V (A) - V (B)] + [V (B) - V (C)] = ε_{1} - I r_{1} + ε_{2} - I r_{2}$
$= (ε_{1} + ε_{2}) - I (r_{1} + r_{2}) = ε_{e q} - I r_{e q}$

Q. Consider first two cells in series as shown in figure the potential difference between the terminals A and C of the combination is

VAC​=ε1​−Ir1​

VAC​=ε2​−Ir2​

VAC​=εeq​−Ireq​

VAC​=2εeq​−Ireq​