Consider a rough horizontal plank with a coefficient of friction μ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination 37° , what is 4μ =?

Question

Consider a rough horizontal plank with a coefficient of friction μ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination 37° , what is 4μ =? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

N=mgcos 37 mgsin 37=f=μ N mgsin 37=μ mgcosâ¡37 μ =(3/4) 4μ =3

Q. Consider a rough horizontal plank with a coefficient of friction $μ$ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination $3 7^{\circ}$ , what is $4 μ = ?$

$N = m g cos 37$
$m g s in 37 = f = μ N$
$m g s in 37 = μ m g cos 37$
$μ = \frac{3}{4}$
$4 μ = 3$

Q. Consider a rough horizontal plank with a coefficient of friction μ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination 37∘ , what is 4μ=?

N=mgcos37 mgsin37=f=μN mgsin37=μmgcos⁡37 μ=43​ 4μ=3

Q. Consider a rough horizontal plank with a coefficient of friction $μ$ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination $3 7^{\circ}$ , what is $4 μ = ?$

$N = m g cos 37$
$m g s in 37 = f = μ N$
$m g s in 37 = μ m g cos 37$
$μ = \frac{3}{4}$
$4 μ = 3$