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Q. Consider a rough horizontal plank with a coefficient of friction $\mu $ . A block is placed on this surface and the plank is slowly raised from a side such that its inclination with horizontal increases. If the block on plank starts sliding at an inclination $37^\circ $ , what is $4\mu =?$

NTA AbhyasNTA Abhyas 2022

Solution:

$N=mgcos 37$
$mgsin 37=f=\mu N$
$mgsin 37=\mu mgcos⁡37$
$\mu =\frac{3}{4}$
$4\mu =3$