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Tardigrade
Question
Mathematics
Consider a cone whose base area is equal to 154 mathrm~cm2 and the slant height is 9 mathrm~cm then
Q. Consider a cone whose base area is equal to
154
cm
2
and the slant height is
9
cm
then
50
228
Mensuration
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A
Curved surface area
=
198
cm
2
B
Total surface area
=
300
cm
2
C
Total surface are
=
352
cm
2
D
Height of the cone
=
4
2
cm
Solution:
∴
π
r
2
=
154
⇒
7
22
×
r
2
=
154
∴
r
=
7
cm
Curved surface area
=
π
r
l
=
7
22
×
7
×
9
=
198
cm
2
Total surface are
=
π
r
l
+
π
r
2
=
198
+
154
=
352
cm
2
As,
h
2
+
r
2
=
l
2
[Where
h
→
height of the cone]
∴
h
2
=
l
2
−
r
2
∴
h
=
9
2
−
7
2
∴
h
=
32
∴
h
=
4
2
cm