Consider a binary mixture of volatile liquids. If at XA=0.2 , the vapour pressure of solution is 580torr , then the mixture could be (PA° = 200 torr , PB° = 600 torr)

Question

Consider a binary mixture of volatile liquids. If at XA=0.2 , the vapour pressure of solution is 580torr , then the mixture could be (PA° = 200 torr , PB° = 600 torr) (A) CHCl3+CH3COCH3 (B) C2H5OH+ Hexane (C) H2O+HNO3 (D) nC6H14+nC7H16

Tardigrade Admin · Accepted Answer

P(ideal)=0.2× 200+0.8× 600 =520torr < P(obs) Solution showing positive deviation.

Q. Consider a binary mixture of volatile liquids. If at $X_{A} = 0.2$ , the vapour pressure of solution is $580 t orr$ , then the mixture could be $(P_{A}^{^{\circ}} = 200 t orr, P_{B}^{^{\circ}} = 600 t orr)$

$C H C l_{3} + C H_{3} COC H_{3}$

$C_{2} H_{5} O H +$ Hexane

$H_{2} O + H N O_{3}$

$n C_{6} H_{14} + n C_{7} H_{16}$

$P_{(i d e a l)} = 0.2 \times 200 + 0.8 \times 600$
$= 520 t orr < P (o b s)$
Solution showing positive deviation.

Q. Consider a binary mixture of volatile liquids. If at XA​=0.2 , the vapour pressure of solution is 580torr , then the mixture could be (PA∘​=200torr,PB∘​=600torr)

CHCl3​+CH3​COCH3​

C2​H5​OH+ Hexane

H2​O+HNO3​

nC6​H14​+nC7​H16​