Consider 35 g of oxygen at room temperature. Calculate the heat that needs to be supplied to raise it's temperature by 80 ° C at constant volume. (molecular weight of oxygen is 32 and R=8.3 J mol- 1K- 1 )

Question

Consider 35 g of oxygen at room temperature. Calculate the heat that needs to be supplied to raise it's temperature by 80 ° C at constant volume. (molecular weight of oxygen is 32 and R=8.3 J mol- 1K- 1 ) (A) 1.52 kJ (B) 3.23 kJ (C) 1.81 kJ (D) 1.62 kJ

Tardigrade Admin · Accepted Answer

Here mass of oxygen (m)=35 g molar mass of O2 (M)=32 g (m o l)- 1 rise in temperature, Δ T=80â ∴ number of moles n=(m/M)=(35/32)=1.09 mol As oxygen is a diatomic gas, then molar specific heat at constant volume is CV=(5/2)R and amount of heat supplied to gas Δ Q=nCVΔ T=1.09× (5/2)R× 80=1.09× (5/2)× 8.3× 80 =1809.4 J=1.8094 kJ=1.81 kJ

Q. Consider $35 g$ of oxygen at room temperature. Calculate the heat that needs to be supplied to raise it's temperature by $80^{\circ} C$ at constant volume. (molecular weight of oxygen is $32$ and $R = 8.3 J m o l^{- 1} K^{- 1}$ )

$1.52 k J$

$3.23 k J$

$1.81 k J$

$1.62 k J$

Q. Consider 35g of oxygen at room temperature. Calculate the heat that needs to be supplied to raise it's temperature by 80∘C at constant volume. (molecular weight of oxygen is 32 and R=8.3Jmol−1K−1 )

1.52kJ

3.23kJ

1.81kJ

1.62kJ

Q. Consider $35 g$ of oxygen at room temperature. Calculate the heat that needs to be supplied to raise it's temperature by $80^{\circ} C$ at constant volume. (molecular weight of oxygen is $32$ and $R = 8.3 J m o l^{- 1} K^{- 1}$ )

$1.52 k J$

$3.23 k J$

$1.81 k J$

$1.62 k J$